49x^2+21x-12=-8

Solution for 49x^2+21x-12=-8 equation:

49x^2+21x-12=-8

We move all terms to the left:

49x^2+21x-12-(-8)=0

We add all the numbers together, and all the variables

49x^2+21x-4=0

a = 49; b = 21; c = -4;
Δ = b2-4ac
Δ = 212-4·49·(-4)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-35}{2*49}=\frac{-56}{98}
=-4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+35}{2*49}=\frac{14}{98}
=1/7
$